How to Get Batch File Path Name Components? I want to know the path name of the directory where the batch file is located.

To get different components of the batch file path name, you can use batch parameter modifiers on %0, which represents the batch file name.

Here is a batch file, Batch-File-Name.bat, that dumps the %0 parameter with different modifiers:

@echo off
rem Batch-File-Name.bat - Show components of the batch file name

echo 0          = %0      
echo ~0         = %~0      
echo ~f0        = %~f0     
echo ~d0        = %~d0     
echo ~p0        = %~p0     
echo ~n0        = %~n0     
echo ~x0        = %~x0     
echo ~s0        = %~s0    
echo ~a0        = %~a0     
echo ~t0        = %~t0     
echo ~z0        = %~z0     
echo ~$PATH:0   = %~$PATH:0
echo ~dp0       = %~dp0      
echo ~pd0       = %~pd0      
echo ~nx0       = %~nx0      
echo ~dp$PATH:0 = %~dp$PATH:0
echo ~ftza0     = %~ftza0    

If you run the above batch file located at C:\fyicenter\Batch-File-Name.bat, you get the following output:

C:\fyicenter>Batch-File-Name.bat

0          = Batch-File-Name.bat
~0         = Batch-File-Name.bat
~f0        = C:\fyicenter\Batch-File-Name.bat
~d0        = C:
~p0        = \fyicenter\
~n0        = Batch-File-Name
~x0        = .bat
~s0        = C:\FYICEN~1\BATCH-~2.BAT
~a0        = --a------
~t0        = 11/22/2033 10:20 PM
~z0        = 552
~$PATH:0   = C:\fyicenter\Batch-File-Name.bat
~dp0       = C:\fyicenter\
~pd0       = C:\fyicenter\
~nx0       = Batch-File-Name.bat
~dp$PATH:0 = C:\fyicenter\
~ftza0     = --a------ 11/22/2033 10:20 PM 552 C:\fyicenter\Batch-File-Name.bat

⇒ Get Batch Parameter as File Path

⇐ Batch Parameter Modifiers

⇑ Working with Parameters and Variables

⇑⇑ Windows Batch File Tutorials